M=m^2-26m+162

Solution for M=m^2-26m+162 equation:

=M^2-26M+162

We move all terms to the left:

-(M^2-26M+162)=0

We get rid of parentheses

-M^2+26M-162=0

We add all the numbers together, and all the variables

-1M^2+26M-162=0

a = -1; b = 26; c = -162;
Δ = b2-4ac
Δ = 262-4·(-1)·(-162)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$M_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{7}}{2*-1}=\frac{-26-2\sqrt{7}}{-2}
$
$M_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{7}}{2*-1}=\frac{-26+2\sqrt{7}}{-2}
$